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Calculations involving molar volume - Higher

The can be used in calculations involving the of solids, and volumes of gases, in reactions.

Calculating a volume from a mass

Worked example

4.6 g of sodium reacts completely with excess water:

2Na(s) + 2H2O(l) 鈫 2NaOH(aq) + H2(g)

Calculate the volume of hydrogen produced. (Ar of Na = 23, molar volume = 24 dm3)

Step 1 - Calculate the amount of sodium

Amount in mol = \(\frac{\textup{mass~in~g}}{A_{\textup{r}}}\)

Amount in mol = \(\frac{\textup{4.6}}{\textup{23}}\)

Amount of sodium = 0.20 mol

Step 2 - Find the amount of hydrogen

From the , the Na:H2 is 2:1

Therefore 0.20 mol of Na produces \(\frac{\textup{0.20}}{\textup{2}}\) = 0.10 mol of H2

Step 3 - Calculate the volume of hydrogen

Volume = amount in mol 脳 molar volume

Volume = 0.10 脳 24

= 2.4 dm3

Question

Calcium carbonate to form calcium oxide and carbon dioxide when it is heated:

CaCO3(s) 鈫 CaO(s) + CO2(g)

Calculate the volume of carbon dioxide produced from completely decomposing 1.0 g of calcium carbonate. (Mr of CaCO3 = 100, molar volume = 24,000 cm3)

Calculating a mass from a volume

Worked example

Lithium hydroxide absorbs carbon dioxide from the air:

2LiOH(s) + CO2(g) 鈫 Li2CO3(s) + H2O(l)

Calculate the mass of lithium hydroxide needed to absorb 12 dm3 of carbon dioxide. (Mr of LiOH = 24, molar volume = 24 dm3)

Step 1 - Calculate the amount of carbon dioxide

Amount in mol = \(\frac{\textup{volume}}{\textup{molar~volume}}\)

Amount in mol = \(\frac{\textup{12}}{\textup{24}}\)

= 0.50 mol

Step 2 - Find the amount of lithium hydroxide

From the balanced equation, the mole ratio LiOH:CO2 is 2:1

Therefore 0.50 mol of CO2 is absorbed by (0.50 脳 2) = 1.0 mol of LiOH

Step 3 - Calculate the mass of lithium hydroxide

Mass in g = Mr 脳 amount in mol

Mass = 24 脳 1.0

= 24 g

Question

Sodium reacts with chlorine to produce sodium chloride:

2Na(s) + Cl2(g) 鈫 2NaCl(s)

Calculate the mass of sodium chloride produced from 960 cm3 of chlorine and an excess of sodium. (Mr of NaCl = 58.5, molar volume = 24,000 cm3 )