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Example

Using bond enthalpies, what is the enthalpy change when hydrogen is added to ethyne to produce ethane?

\(C_{2}H_{2} (g) + 2H_{2} (g)\rightarrow C_{2}H_{6} (g) \)

To answer this we must look at what types of bonds must be broken in the reactants and formed in the products.

Follow these simple steps:

Step one

Draw the full structural formulae of all the molecules from the equation. This will show exactly what bonds are involved.

An ethyne molecule (C2H2) plus two hydrogen molecules (two times H2) produces a molecule of ethane (C2H6).

Step two

Make a list of all the bonds being broken in the reactants and their bond enthalpies using the data book.

Bond breaking

\(1\times{C}\equiv{C}=838kJ\)

\(2 \times C - H = 2 \times 412 = 824 kJ\)

\(2 \times H - H = 2 \times 436 = 872 kJ\)

\(Total\,\, put\,\, in = 2534 kJ\)

Step three

Repeat this process for the bond making steps and all new bonds formed.

Bond making

\(1 \times C - C = 348 kJ\)

\(6 \times C - H = 6 \times 412 = - 2472 kJ\)

\(Total\,\, given\,\, out = -2820 kJ\)

Step four

Calculate the enthalpy change for the reaction, remembering that bond breaking is an endothermic process and bond making is an exothermic process.

\(\Delta H = 2534 + (-2820) = 2534 - 2820 = -286 kJ mol^{-1}\)

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