Efficiency
From the conservation of energyThe principle that the total energy of a system stays the same, that energy cannot be created or destroyed (only stored or transferred)., we know that energy is not used up but simply changes from one form to another.
The total amount of energy stays the same.
However, not all of the energy used in a particular process or device is useful.
Some is always wasted, for example, as heat, sound, and light.
The efficiency of a device is a measure of how much of the input energy appears as useful output energy.
The more energy a device wastes, the less efficient it is.
This is when:
- useful output energy is measured in joules, J;
- input energy is the total energy in J supplied to a device.
Calculating efficiency
Example: filament lamp
A filament lamp converts 100 J of electrical energy into 90 J of heat energy and 10 J of light energy.
Calculate the efficiency of the lamp.
Answer
Efficiency = \(\frac{\text{useful output energy}}{\text{total input energy}}\)
Useful output energy = 10 J
Total input energy = 100 J
efficiency = \(\frac{\text{10}}{\text{100}}\)
efficiency = 0.1
This means that 0.1 (or 10 %) of the electrical energy supplied is converted to light energy.
The light bulb is not very efficient since most of the energy supplied is not converted to useful light energy.
Most of the energy will have been converted to wasted heat energy.
This is why light bulbs become very hot when they are switched on.
Another way of thinking about this is that for every 拢100 spent on lighting, 拢10 is spent on the light and 拢90 is wasted heating the surroundings.
The efficiency of a device can never be greater than 1 otherwise energy would be created, and the principle of conservation of energy violated.
Question
An LED lamp converts 100 J of electrical energy into 25 J of heat energy and 75 J of light energy.
Calculate the efficiency of the lamp.
Efficiency = \(\frac{\text{useful output energy}}{\text{total input energy}}\).
Useful output energy = 75 J.
Total input energy = 100 J.
Efficiency = \(\frac{75}{100}\).
Efficiency = 0.75.
This means that 0.75 (or 75%) of the electrical energy supplied is transferred as light energy.
For every 拢100 spent on lighting, 拢75 is spent on the light and only 拢25 is wasted heating the surroundings.
The LED lamp is much more efficient than the filament lamp and can help save money.
Question
The energy supplied to a light bulb is 200 J. A total of 28 J of this is usefully transferred. How efficient is the light bulb?
Efficiency = \(\frac{\text{useful output energy}}{\text{total input energy}}\)
Useful output energy = 28 J
Total input energy = 200 J
efficiency = \(\frac{\text{28}}{\text{200}}\)
efficiency = 0.14
This means that 0.14 (or 14%) of the electrical energy supplied is transferred as light energy.
Question
A hairdryer has an efficiency of 0.4.
1. What does an efficiency of 0.4 mean?
2. How much electrical energy has to be supplied for the hairdryer to output 600 J of useful energy?
1. An efficiency of 0.4 means that 0.4 of the total input electrical energy is converted into useful output energy.
2. Efficiency = \(\frac{\text{useful output energy}}{\text{total input energy}}\)
efficiency = 0.4
Useful output energy = 600 J
\(0.4 = \frac{\text{600}}{\text{total input energy}}\)
And so:
Total input energy = \(\frac{\text{600}}{\text{0.4}}\)
Total input energy = 1500 J
The hairdryer must be supplied with 1500 J of energy.